dosss
March 17, 2014, 9:35pm
1922
Oh darnit, I knew something was wrong in there
Heh
tf2 about 7 gigs of stuff but most of it is hats
Yup. xD
(Never Play Loadout if you don’t like nudity fps)
dosss
March 20, 2014, 6:53pm
1925
No class today
Butt the first test starts tomorrow…
Gabrui
March 21, 2014, 12:54am
1926
So, are we going to reach the 10,000 posts? Lol
dosss
March 21, 2014, 2:23am
1927
Buttercourse
That is the only reason of this thread
Gabrui
March 22, 2014, 1:08am
1928
Definitively, I won ;D
THIS IS THE LAST COMMENT.
TOPIC CLOSED.
//EOF.
Gabrui
March 22, 2014, 9:43pm
1930
Let mathematics decide it! ;D
Define the following serie: S = 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1…
So, if the sum is one, I win, otherwise you must give another anwser and prove it is right.
My turn: S = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1)… = 1 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0… = 1
So, I won!
SnIpEr
March 22, 2014, 10:48pm
1931
Let mathematics decide it! ;D
Define the following serie: S = 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1…
So, if the sum is one, I win, otherwise you must give another anwser and prove it is right.
My turn: S = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1)… = 1 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0… = 1
So, I won!
that serie can be defined with Σ((-1)^n) with n ∈ [2,∞[, and (-1)^∞ is an indetermination, there is no way to know if ∞ is even or odd
so your answer is wrong, it cant either be 1 or 0, it cant be calculated
edit: was thinking about 1+0+1+0+1+0+… my bad sorry
Gabrui
March 22, 2014, 11:30pm
1933
Sniper, thats is the point of that series. As that, this topic:
I can get any racional number I want with this sum:
S = 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 ......
S = 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 .......
----------------------------------------------------------
S + S = 1 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0........
2S = 1
S = 1/2
dosss
March 23, 2014, 12:44am
1934
Good, good, keep posting :3
* dosss is happy
Gabrui
March 23, 2014, 1:37pm
1935
My comment will be the last one, ha!
SnIpEr
March 23, 2014, 2:03pm
1936
You shouldn’t play around with math, creating rules by yourself n stuff specially when they don’t really make sense.
S + S = Σ((-1)^n) + Σ((-1)^n) = 2S = 2Σ((-1)^n) = either 2 or 0
The calc you were trying to show was:
S + Σ((-1)^(k+1)); k ∈ [3,∞[ =
= Σ((-1)^n) + Σ((-1)^(k+1)); n ∈ [2,∞[ =
= (-1)^2 + Σ((-1)^k) + Σ((-1)^(k+1)) =
= 1 + Σ((-1)^k + (-1)^(k+1)) =
= 1 + Σ((-1)^0 * (-1)^k + (-1)^1 * (-1)^k) =
= 1 + Σ(((-1)^0 + (-1)^1) * (-1)^k) =
= 1 + Σ(0*(-1)^k) =
= 1 + Σ(0) = 1
In the back of my head, i vaguely remember something like this
nods in understanding while eating paste in a corner
dosss
March 23, 2014, 3:15pm
1939
* dosss is contemplating the universe while eating cereal
Gabrui
March 23, 2014, 3:34pm
1940
Hey Sniper, It wasnt me that defined that series, I am just playing with it and comparing it to this topic, as there will be no last comment:
It is an Divergent Alternating Series, and it’s very strange:
In mathematics, the infinite series 1 − 1 + 1 − 1 + ⋯, also written
is sometimes called Grandi's series, after Italian mathematician, philosopher, and priest Guido Grandi, who gave a memorable treatment of the series in 1703. It is a divergent series, meaning that it lacks a sum in the usual sense. On the other hand, its Cesàro sum is 1/2. But this contradicts the Law of Closure in Integers which states that Addition, Multiplication and Subtraction are closed under Integers, i.e if you add 2 or ...